Example of Regular Expression

Ex. 6:
Find a regular expression corresponding to the language of all strings over the alphabet { a, b } that contain no more than one occurence of the string aa.

Solution:
If there is one substring aa in a string of the language, then that aa can be followed by any number of b. If an a comes after that aa, then that a must be preceded by b because otherwise there are two occurences of aa. Hence any string that follows aa is represented by ( b + ba )*. On the other hand if an a precedes the aa, then it must be followed by b. Hence a string preceding the aa can be represented by ( b + ab )*. Hence if a string of the language contains aa then it corresponds to the regular expression ( b + ab )*aa( b + ba )* .

If there is no aa but at least one a exists in a string of the language, then applying the same argument as for aa to a, ( b + ab )*a( b + ba )* is obtained as a regular expression corresponding to such strings.

If there may not be any a in a string of the language, then applying the same argument as for aa to , ( b + ab )*( b + ba )* is obtained as a regular expression corresponding to such strings.
Altogether ( b + ab )*( + a + aa )( b + ba )* is a regular expression for the language.